- Update on 2013/01/05
-
Xiao Nan in the comments pointed out that
apply(combn(letters, 2), 2, paste0, collapse = '')
was wrong for all two-letter usernames, and indeed it was. It is not a combination problem. Now I use his elegantouter()
solution. One can also useexpand.grid(letters, letters)
.
GitHub decided to take off their downloads service, and I was very unhappy with this decision. This means I have to migrate several files to other places, and update links accordingly. I saw Bitbucket still provides the service, so I want to migrate my files there.
Sadly my name yihui
was already taken on Bitbucket, so I hoped I could get a
short name, which made me think how I could check the availability of a username
via programming, and here was my solution with the RCurl package:
library(RCurl)
test_user = function(site = 'https://bitbucket.org/',
candidates = c(0:9, letters)) {
for (i in candidates) {
if (!url.exists(paste0(site, i))) message(i)
Sys.sleep(runif(1, 0, .1)) # be nice
}
}
# examples
test_user()
# two-letter names
test_user(candidates = as.vector(outer(letters, letters, 'paste0')))
# check github
test_user('https://github.com/')
As of the time of this blog post, there are no two-letter usernames left on
GitHub, but some are still available on Bitbucket, e.g. by
and eq
, etc, and
the number 4
is also available.